Solve -10+1-9x+6-8x+x

$$- 10 + 1 - 9 x + 6 - 8 x + x$$

Evaluate

$$-16x-3$$

Solution Steps

Add -10 and 1 to get -9.

$$-9-9x+6-8x+x$$

Add -9 and 6 to get -3.

$$-3-9x-8x+x$$

Combine -9x and -8x to get -17x.

$$-3-17x+x$$

Combine -17x and x to get -16x.

$$-3-16x$$

Differentiate w.r.t. x

$$-16$$

Steps Using Derivative Rule for Sum

Add -10 and 1 to get -9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-9-9x+6-8x+x)$$

Add -9 and 6 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3-9x-8x+x)$$

Combine -9x and -8x to get -17x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3-17x+x)$$

Combine -17x and x to get -16x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3-16x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-16x^{1-1}$$

Subtract 1 from 1.

$$-16x^{0}$$

For any term t except 0, t^{0}=1.

$$-16$$