Solve -1-(1-05)*1/3*[19-(-5)div(-1/5)]

$$- 1 - ( 1 - 05 ) \times \frac { 1 } { 3 } \times [ 19 - ( - 5 ) \div ( - \frac { 1 } { 5 } ) ]$$

Evaluate

$$1$$

Solution Steps

Multiply 0 and 5 to get 0.

$$-1-\left(1-0\right)\times \frac{1}{3}\left(19-\frac{-5}{-\frac{1}{5}}\right)$$

Subtract 0 from 1 to get 1.

$$-1-1\times \frac{1}{3}\left(19-\frac{-5}{-\frac{1}{5}}\right)$$

Multiply 1 and \frac{1}{3} to get \frac{1}{3}.

$$-1-\frac{1}{3}\left(19-\frac{-5}{-\frac{1}{5}}\right)$$

Divide -5 by -\frac{1}{5} by multiplying -5 by the reciprocal of -\frac{1}{5}.

$$-1-\frac{1}{3}\left(19-\left(-5\left(-5\right)\right)\right)$$

Multiply -5 and -5 to get 25.

$$-1-\frac{1}{3}\left(19-25\right)$$

Subtract 25 from 19 to get -6.

$$-1-\frac{1}{3}\left(-6\right)$$

Multiply \frac{1}{3} and -6 to get \frac{-6}{3}.

$$-1-\frac{-6}{3}$$

Divide -6 by 3 to get -2.

$$-1-\left(-2\right)$$

The opposite of -2 is 2.

$$-1+2$$

Add -1 and 2 to get 1.

$$1$$

Factor

$$1$$