Solve -1|-sqrt{4}+(pi-3)^0+2^-2

$$- 1 | - \sqrt { 4 } + ( \pi - 3 ) ^ { 0 } + 2 ^ { - 2 }$$

Evaluate

$$-\frac{3}{4}=-0.75$$

Solution Steps

Calculate the square root of 4 and get 2.

$$-|-2+\left(\pi -3\right)^{0}+2^{-2}|$$

Calculate \pi -3 to the power of 0 and get 1.

$$-|-2+1+2^{-2}|$$

Add -2 and 1 to get -1.

$$-|-1+2^{-2}|$$

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$-|-1+\frac{1}{4}|$$

Add -1 and \frac{1}{4} to get -\frac{3}{4}.

$$-|-\frac{3}{4}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{3}{4} is \frac{3}{4}.

$$-\frac{3}{4}$$

Factor

$$-\frac{3}{4} = -0.75$$