Solve -17/9div(-41/3)=

$$- 1 \frac { 7 } { 9 } \div ( - 4 \frac { 1 } { 3 } ) =$$

Evaluate

$$\frac{16}{39}\approx 0.41025641$$

Solution Steps

Multiply 1 and 9 to get 9.

$$\frac{-\frac{9+7}{9}}{-\frac{4\times 3+1}{3}}$$

Add 9 and 7 to get 16.

$$\frac{-\frac{16}{9}}{-\frac{4\times 3+1}{3}}$$

Multiply 4 and 3 to get 12.

$$\frac{-\frac{16}{9}}{-\frac{12+1}{3}}$$

Add 12 and 1 to get 13.

$$\frac{-\frac{16}{9}}{-\frac{13}{3}}$$

Divide -\frac{16}{9} by -\frac{13}{3} by multiplying -\frac{16}{9} by the reciprocal of -\frac{13}{3}.

$$-\frac{16}{9}\left(-\frac{3}{13}\right)$$

Multiply -\frac{16}{9} times -\frac{3}{13} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-16\left(-3\right)}{9\times 13}$$

Do the multiplications in the fraction \frac{-16\left(-3\right)}{9\times 13}.

$$\frac{48}{117}$$

Reduce the fraction \frac{48}{117} to lowest terms by extracting and canceling out 3.

$$\frac{16}{39}$$

Factor

$$\frac{2 ^ {4}}{3 \cdot 13} = 0.41025641025641024$$