Solve -123/42*31/13=

$$- 1 \frac { 23 } { 42 } \cdot 3 \frac { 1 } { 13 } =$$

Evaluate

$$-\frac{100}{21}\approx -4.761904762$$

Solution Steps

Multiply 1 and 42 to get 42.

$$\left(-\frac{42+23}{42}\right)\times \frac{3\times 13+1}{13}$$

Add 42 and 23 to get 65.

$$-\frac{65}{42}\times \frac{3\times 13+1}{13}$$

Multiply 3 and 13 to get 39.

$$-\frac{65}{42}\times \frac{39+1}{13}$$

Add 39 and 1 to get 40.

$$-\frac{65}{42}\times \frac{40}{13}$$

Multiply -\frac{65}{42} times \frac{40}{13} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-65\times 40}{42\times 13}$$

Do the multiplications in the fraction \frac{-65\times 40}{42\times 13}.

$$\frac{-2600}{546}$$

Reduce the fraction \frac{-2600}{546} to lowest terms by extracting and canceling out 26.

$$-\frac{100}{21}$$

Factor

$$-\frac{100}{21} = -4\frac{16}{21} = -4.761904761904762$$