Solve -117/16+41/6

$$- 1 \frac { 17 } { 16 } + 4 \frac { 1 } { 6 }$$

Evaluate

$$\frac{101}{48}\approx 2.104166667$$

Solution Steps

Multiply 1 and 16 to get 16.

$$-\frac{16+17}{16}+\frac{4\times 6+1}{6}$$

Add 16 and 17 to get 33.

$$-\frac{33}{16}+\frac{4\times 6+1}{6}$$

Multiply 4 and 6 to get 24.

$$-\frac{33}{16}+\frac{24+1}{6}$$

Add 24 and 1 to get 25.

$$-\frac{33}{16}+\frac{25}{6}$$

Least common multiple of 16 and 6 is 48. Convert -\frac{33}{16} and \frac{25}{6} to fractions with denominator 48.

$$-\frac{99}{48}+\frac{200}{48}$$

Since -\frac{99}{48} and \frac{200}{48} have the same denominator, add them by adding their numerators.

$$\frac{-99+200}{48}$$

Add -99 and 200 to get 101.

$$\frac{101}{48}$$

Factor

$$\frac{101}{2 ^ {4} \cdot 3} = 2\frac{5}{48} = 2.1041666666666665$$