Solve -11/2-3/4:(11/2-1/3)^2=

$$- 1 \frac { 1 } { 2 } - \frac { 3 } { 4 } : ( 1 \frac { 1 } { 2 } - \frac { 1 } { 3 } ) ^ { 2 } =$$

Evaluate

$$-\frac{201}{98}\approx -2.051020408$$

Solution Steps

Multiply 1 and 2 to get 2.

$$-\frac{2+1}{2}-\frac{\frac{3}{4}}{\left(\frac{1\times 2+1}{2}-\frac{1}{3}\right)^{2}}$$

Add 2 and 1 to get 3.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{1\times 2+1}{2}-\frac{1}{3}\right)^{2}}$$

Multiply 1 and 2 to get 2.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{2+1}{2}-\frac{1}{3}\right)^{2}}$$

Add 2 and 1 to get 3.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{3}{2}-\frac{1}{3}\right)^{2}}$$

Subtract \frac{1}{3} from \frac{3}{2} to get \frac{7}{6}.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\left(\frac{7}{6}\right)^{2}}$$

Calculate \frac{7}{6} to the power of 2 and get \frac{49}{36}.

$$-\frac{3}{2}-\frac{\frac{3}{4}}{\frac{49}{36}}$$

Divide \frac{3}{4} by \frac{49}{36} by multiplying \frac{3}{4} by the reciprocal of \frac{49}{36}.

$$-\frac{3}{2}-\frac{3}{4}\times \frac{36}{49}$$

Multiply \frac{3}{4} and \frac{36}{49} to get \frac{27}{49}.

$$-\frac{3}{2}-\frac{27}{49}$$

Subtract \frac{27}{49} from -\frac{3}{2} to get -\frac{201}{98}.

$$-\frac{201}{98}$$

Factor

$$-\frac{201}{98} = -2\frac{5}{98} = -2.0510204081632653$$