Solve -1^4-(1-0.5)*2^3/3div[-2-(-3)^2]

$$- 1 ^ { 4 } - ( 1 - 0.5 ) \times \frac { 2 ^ { 3 } } { 3 } \div [ - 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$-\frac{29}{33}\approx -0.878787879$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$-1-\frac{\left(1-0.5\right)\times \frac{2^{3}}{3}}{-2-\left(-3\right)^{2}}$$

Subtract 0.5 from 1 to get 0.5.

$$-1-\frac{0.5\times \frac{2^{3}}{3}}{-2-\left(-3\right)^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$-1-\frac{0.5\times \frac{8}{3}}{-2-\left(-3\right)^{2}}$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$-1-\frac{\frac{1}{2}\times \frac{8}{3}}{-2-\left(-3\right)^{2}}$$

Multiply \frac{1}{2} times \frac{8}{3} by multiplying numerator times numerator and denominator times denominator.

$$-1-\frac{\frac{1\times 8}{2\times 3}}{-2-\left(-3\right)^{2}}$$

Do the multiplications in the fraction \frac{1\times 8}{2\times 3}.

$$-1-\frac{\frac{8}{6}}{-2-\left(-3\right)^{2}}$$

Reduce the fraction \frac{8}{6} to lowest terms by extracting and canceling out 2.

$$-1-\frac{\frac{4}{3}}{-2-\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$-1-\frac{\frac{4}{3}}{-2-9}$$

Subtract 9 from -2 to get -11.

$$-1-\frac{\frac{4}{3}}{-11}$$

Express \frac{\frac{4}{3}}{-11} as a single fraction.

$$-1-\frac{4}{3\left(-11\right)}$$

Multiply 3 and -11 to get -33.

$$-1-\frac{4}{-33}$$

Fraction \frac{4}{-33} can be rewritten as -\frac{4}{33} by extracting the negative sign.

$$-1-\left(-\frac{4}{33}\right)$$

The opposite of -\frac{4}{33} is \frac{4}{33}.

$$-1+\frac{4}{33}$$

Convert -1 to fraction -\frac{33}{33}.

$$-\frac{33}{33}+\frac{4}{33}$$

Since -\frac{33}{33} and \frac{4}{33} have the same denominator, add them by adding their numerators.

$$\frac{-33+4}{33}$$

Add -33 and 4 to get -29.

$$-\frac{29}{33}$$

Factor

$$-\frac{29}{33} = -0.8787878787878788$$