Solve -1^4-(1-0.5)^1+3*[2-(-3)^2]

$$- 1 ^ { 4 } - ( 1 - 0.5 ) ^ { 1 } + 3 \times [ 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$-22.5$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$-1-\left(1-0.5\right)^{1}+3\left(2-\left(-3\right)^{2}\right)$$

Subtract 0.5 from 1 to get 0.5.

$$-1-0.5^{1}+3\left(2-\left(-3\right)^{2}\right)$$

Calculate 0.5 to the power of 1 and get 0.5.

$$-1-0.5+3\left(2-\left(-3\right)^{2}\right)$$

Subtract 0.5 from -1 to get -1.5.

$$-1.5+3\left(2-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$-1.5+3\left(2-9\right)$$

Subtract 9 from 2 to get -7.

$$-1.5+3\left(-7\right)$$

Multiply 3 and -7 to get -21.

$$-1.5-21$$

Subtract 21 from -1.5 to get -22.5.

$$-22.5$$

Factor

$$-22.5$$