Solve -1^4-1/6*[-2^2-(-3)^3]

$$- 1 ^ { 4 } - \frac { 1 } { 6 } \times [ - 2 ^ { 2 } - ( - 3 ) ^ { 3 } ]$$

Evaluate

$$-\frac{29}{6}\approx -4.833333333$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$-1-\frac{1}{6}\left(-2^{2}-\left(-3\right)^{3}\right)$$

Calculate 2 to the power of 2 and get 4.

$$-1-\frac{1}{6}\left(-4-\left(-3\right)^{3}\right)$$

Calculate -3 to the power of 3 and get -27.

$$-1-\frac{1}{6}\left(-4-\left(-27\right)\right)$$

The opposite of -27 is 27.

$$-1-\frac{1}{6}\left(-4+27\right)$$

Add -4 and 27 to get 23.

$$-1-\frac{1}{6}\times 23$$

Multiply \frac{1}{6} and 23 to get \frac{23}{6}.

$$-1-\frac{23}{6}$$

Convert -1 to fraction -\frac{6}{6}.

$$-\frac{6}{6}-\frac{23}{6}$$

Since -\frac{6}{6} and \frac{23}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-6-23}{6}$$

Subtract 23 from -6 to get -29.

$$-\frac{29}{6}$$

Factor

$$-\frac{29}{6} = -4\frac{5}{6} = -4.833333333333333$$