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\frac{-1}{5^{2}}\left(-\frac{6}{3}\right)+|\frac{0.8\times 4+7}{4}-1|
Calculate 1 to the power of 4 and get 1.
\frac{-1}{25}\left(-\frac{6}{3}\right)+|\frac{0.8\times 4+7}{4}-1|
Calculate 5 to the power of 2 and get 25.
-\frac{1}{25}\left(-\frac{6}{3}\right)+|\frac{0.8\times 4+7}{4}-1|
Fraction \frac{-1}{25} can be rewritten as -\frac{1}{25} by extracting the negative sign.
-\frac{1}{25}\left(-2\right)+|\frac{0.8\times 4+7}{4}-1|
Divide 6 by 3 to get 2.
\frac{-\left(-2\right)}{25}+|\frac{0.8\times 4+7}{4}-1|
Express -\frac{1}{25}\left(-2\right) as a single fraction.
\frac{2}{25}+|\frac{0.8\times 4+7}{4}-1|
Multiply -1 and -2 to get 2.
\frac{2}{25}+|\frac{3.2+7}{4}-1|
Multiply 0.8 and 4 to get 3.2.
\frac{2}{25}+|\frac{10.2}{4}-1|
Add 3.2 and 7 to get 10.2.
\frac{2}{25}+|\frac{102}{40}-1|
Expand \frac{10.2}{4} by multiplying both numerator and the denominator by 10.
\frac{2}{25}+|\frac{51}{20}-1|
Reduce the fraction \frac{102}{40} to lowest terms by extracting and canceling out 2.
\frac{2}{25}+|\frac{51}{20}-\frac{20}{20}|
Convert 1 to fraction \frac{20}{20}.
\frac{2}{25}+|\frac{51-20}{20}|
Since \frac{51}{20} and \frac{20}{20} have the same denominator, subtract them by subtracting their numerators.
\frac{2}{25}+|\frac{31}{20}|
Subtract 20 from 51 to get 31.
\frac{2}{25}+\frac{31}{20}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of \frac{31}{20} is \frac{31}{20}.
\frac{8}{100}+\frac{155}{100}
Least common multiple of 25 and 20 is 100. Convert \frac{2}{25} and \frac{31}{20} to fractions with denominator 100.
\frac{8+155}{100}
Since \frac{8}{100} and \frac{155}{100} have the same denominator, add them by adding their numerators.
\frac{163}{100}
Add 8 and 155 to get 163.