Solve -1^4+|3-5|-16div(-2)*1/2

$$- 1 ^ { 4 } + | 3 - 5 | - 16 \div ( - 2 ) \times \frac { 1 } { 2 }$$

Evaluate

$$5$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$-1+|3-5|-\frac{16}{-2}\times \frac{1}{2}$$

Subtract 5 from 3 to get -2.

$$-1+|-2|-\frac{16}{-2}\times \frac{1}{2}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.

$$-1+2-\frac{16}{-2}\times \frac{1}{2}$$

Add -1 and 2 to get 1.

$$1-\frac{16}{-2}\times \frac{1}{2}$$

Divide 16 by -2 to get -8.

$$1-\left(-8\times \frac{1}{2}\right)$$

Multiply -8 and \frac{1}{2} to get \frac{-8}{2}.

$$1-\frac{-8}{2}$$

Divide -8 by 2 to get -4.

$$1-\left(-4\right)$$

The opposite of -4 is 4.

$$1+4$$

Add 1 and 4 to get 5.

$$5$$

Factor

$$5$$