Solve -1^3-(1-0.5)*1/7*[2-(-3)^2]

$$- 1 ^ { 3 } - ( 1 - 0.5 ) \times \frac { 1 } { 7 } \times [ 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$-0.5$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$-1-\left(1-0.5\right)\times \frac{1}{7}\left(2-\left(-3\right)^{2}\right)$$

Subtract 0.5 from 1 to get 0.5.

$$-1-0.5\times \frac{1}{7}\left(2-\left(-3\right)^{2}\right)$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$-1-\frac{1}{2}\times \frac{1}{7}\left(2-\left(-3\right)^{2}\right)$$

Multiply \frac{1}{2} times \frac{1}{7} by multiplying numerator times numerator and denominator times denominator.

$$-1-\frac{1\times 1}{2\times 7}\left(2-\left(-3\right)^{2}\right)$$

Do the multiplications in the fraction \frac{1\times 1}{2\times 7}.

$$-1-\frac{1}{14}\left(2-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$-1-\frac{1}{14}\left(2-9\right)$$

Subtract 9 from 2 to get -7.

$$-1-\frac{1}{14}\left(-7\right)$$

Multiply \frac{1}{14} and -7 to get \frac{-7}{14}.

$$-1-\frac{-7}{14}$$

Reduce the fraction \frac{-7}{14} to lowest terms by extracting and canceling out 7.

$$-1-\left(-\frac{1}{2}\right)$$

The opposite of -\frac{1}{2} is \frac{1}{2}.

$$-1+\frac{1}{2}$$

Convert -1 to fraction -\frac{2}{2}.

$$-\frac{2}{2}+\frac{1}{2}$$

Since -\frac{2}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{-2+1}{2}$$

Add -2 and 1 to get -1.

$$-\frac{1}{2}$$

Factor

$$-0.5$$