Solve -1^3-(1-0.5)div1/3*[6-(-2)^2]

$$- 1 ^ { 3 } - ( 1 - 0.5 ) \div \frac { 1 } { 3 } \times [ 6 - ( - 2 ) ^ { 2 } ]$$

Evaluate

$$-4$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$-1-\frac{1-0.5}{\frac{1}{3}}\left(6-\left(-2\right)^{2}\right)$$

Subtract 0.5 from 1 to get 0.5.

$$-1-\frac{0.5}{\frac{1}{3}}\left(6-\left(-2\right)^{2}\right)$$

Divide 0.5 by \frac{1}{3} by multiplying 0.5 by the reciprocal of \frac{1}{3}.

$$-1-0.5\times 3\left(6-\left(-2\right)^{2}\right)$$

Multiply 0.5 and 3 to get 1.5.

$$-1-1.5\left(6-\left(-2\right)^{2}\right)$$

Calculate -2 to the power of 2 and get 4.

$$-1-1.5\left(6-4\right)$$

Subtract 4 from 6 to get 2.

$$-1-1.5\times 2$$

Multiply 1.5 and 2 to get 3.

$$-1-3$$

Subtract 3 from -1 to get -4.

$$-4$$

Factor

$$-4$$