Solve -1^3-1/6*1^2+0

$$- 1 ^ { 3 } - \frac { 1 } { 6 } \times 1 ^ { 2 } + 0$$

Evaluate

$$-\frac{7}{6}\approx -1.166666667$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$-1-\frac{1}{6}\times 1^{2}+0$$

Calculate 1 to the power of 2 and get 1.

$$-1-\frac{1}{6}\times 1+0$$

Multiply \frac{1}{6} and 1 to get \frac{1}{6}.

$$-1-\frac{1}{6}+0$$

Convert -1 to fraction -\frac{6}{6}.

$$-\frac{6}{6}-\frac{1}{6}+0$$

Since -\frac{6}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-6-1}{6}+0$$

Subtract 1 from -6 to get -7.

$$-\frac{7}{6}+0$$

Add -\frac{7}{6} and 0 to get -\frac{7}{6}.

$$-\frac{7}{6}$$

Factor

$$-\frac{7}{6} = -1\frac{1}{6} = -1.1666666666666667$$