Solve -1^2020-(1-0*5)*1/3*[2-(-3)^2]

$$- 1 ^ { 2020 } - ( 1 - 0 \cdot 5 ) \times \frac { 1 } { 3 } \times [ 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Calculate 1 to the power of 2020 and get 1.

$$-1-\left(1-0\times 5\right)\times \frac{1}{3}\left(2-\left(-3\right)^{2}\right)$$

Multiply 0 and 5 to get 0.

$$-1-\left(1-0\right)\times \frac{1}{3}\left(2-\left(-3\right)^{2}\right)$$

Subtract 0 from 1 to get 1.

$$-1-1\times \frac{1}{3}\left(2-\left(-3\right)^{2}\right)$$

Multiply 1 and \frac{1}{3} to get \frac{1}{3}.

$$-1-\frac{1}{3}\left(2-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$-1-\frac{1}{3}\left(2-9\right)$$

Subtract 9 from 2 to get -7.

$$-1-\frac{1}{3}\left(-7\right)$$

Multiply \frac{1}{3} and -7 to get \frac{-7}{3}.

$$-1-\frac{-7}{3}$$

Fraction \frac{-7}{3} can be rewritten as -\frac{7}{3} by extracting the negative sign.

$$-1-\left(-\frac{7}{3}\right)$$

The opposite of -\frac{7}{3} is \frac{7}{3}.

$$-1+\frac{7}{3}$$

Convert -1 to fraction -\frac{3}{3}.

$$-\frac{3}{3}+\frac{7}{3}$$

Since -\frac{3}{3} and \frac{7}{3} have the same denominator, add them by adding their numerators.

$$\frac{-3+7}{3}$$

Add -3 and 7 to get 4.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$