Solve -1^2018-1/5*[4-(-3)^2]

$$- 1 ^ { 2018 } - \frac { 1 } { 5 } \times [ 4 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$0$$

Solution Steps

Calculate 1 to the power of 2018 and get 1.

$$-1-\frac{1}{5}\left(4-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$-1-\frac{1}{5}\left(4-9\right)$$

Subtract 9 from 4 to get -5.

$$-1-\frac{1}{5}\left(-5\right)$$

Multiply \frac{1}{5} and -5 to get \frac{-5}{5}.

$$-1-\frac{-5}{5}$$

Divide -5 by 5 to get -1.

$$-1-\left(-1\right)$$

The opposite of -1 is 1.

$$-1+1$$

Add -1 and 1 to get 0.

$$0$$

Factor

$$0$$