Solve -1^2018+(-2)^3*(-1/2)-|-1-2|

$$- 1 ^ { 2018 } + ( - 2 ) ^ { 3 } \times ( - \frac { 1 } { 2 } ) - | - 1 - 2 |$$

Evaluate

$$0$$

Solution Steps

Calculate 1 to the power of 2018 and get 1.

$$-1+\left(-2\right)^{3}\left(-\frac{1}{2}\right)-|-1-2|$$

Calculate -2 to the power of 3 and get -8.

$$-1-8\left(-\frac{1}{2}\right)-|-1-2|$$

Express -8\left(-\frac{1}{2}\right) as a single fraction.

$$-1+\frac{-8\left(-1\right)}{2}-|-1-2|$$

Multiply -8 and -1 to get 8.

$$-1+\frac{8}{2}-|-1-2|$$

Divide 8 by 2 to get 4.

$$-1+4-|-1-2|$$

Add -1 and 4 to get 3.

$$3-|-1-2|$$

Subtract 2 from -1 to get -3.

$$3-|-3|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$3-3$$

Subtract 3 from 3 to get 0.

$$0$$

Factor

$$0$$