Solve -1^2-(3-7)^2-2*(-1)^3

$$- 1 ^ { 2 } - ( 3 - 7 ) ^ { 2 } - 2 \times ( - 1 ) ^ { 3 }$$

Evaluate

$$-15$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$-1-\left(3-7\right)^{2}-2\left(-1\right)^{3}$$

Subtract 7 from 3 to get -4.

$$-1-\left(-4\right)^{2}-2\left(-1\right)^{3}$$

Calculate -4 to the power of 2 and get 16.

$$-1-16-2\left(-1\right)^{3}$$

Subtract 16 from -1 to get -17.

$$-17-2\left(-1\right)^{3}$$

Calculate -1 to the power of 3 and get -1.

$$-17-2\left(-1\right)$$

Multiply 2 and -1 to get -2.

$$-17-\left(-2\right)$$

The opposite of -2 is 2.

$$-17+2$$

Add -17 and 2 to get -15.

$$-15$$

Factor

$$-15$$