Solve -1^2+[7/4+8*(-3)]*0.5-(-5)^2

$$- 1 ^ { 2 } + [ \frac { 7 } { 4 } + 8 \times ( - 3 ) ] \times 0.5 - ( - 5 ) ^ { 2 }$$

Evaluate

$$-37.125$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$-1+\left(\frac{7}{4}+8\left(-3\right)\right)\times 0.5-\left(-5\right)^{2}$$

Multiply 8 and -3 to get -24.

$$-1+\left(\frac{7}{4}-24\right)\times 0.5-\left(-5\right)^{2}$$

Convert 24 to fraction \frac{96}{4}.

$$-1+\left(\frac{7}{4}-\frac{96}{4}\right)\times 0.5-\left(-5\right)^{2}$$

Since \frac{7}{4} and \frac{96}{4} have the same denominator, subtract them by subtracting their numerators.

$$-1+\frac{7-96}{4}\times 0.5-\left(-5\right)^{2}$$

Subtract 96 from 7 to get -89.

$$-1-\frac{89}{4}\times 0.5-\left(-5\right)^{2}$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$-1-\frac{89}{4}\times \frac{1}{2}-\left(-5\right)^{2}$$

Multiply -\frac{89}{4} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$-1+\frac{-89}{4\times 2}-\left(-5\right)^{2}$$

Do the multiplications in the fraction \frac{-89}{4\times 2}.

$$-1+\frac{-89}{8}-\left(-5\right)^{2}$$

Fraction \frac{-89}{8} can be rewritten as -\frac{89}{8} by extracting the negative sign.

$$-1-\frac{89}{8}-\left(-5\right)^{2}$$

Convert -1 to fraction -\frac{8}{8}.

$$-\frac{8}{8}-\frac{89}{8}-\left(-5\right)^{2}$$

Since -\frac{8}{8} and \frac{89}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-8-89}{8}-\left(-5\right)^{2}$$

Subtract 89 from -8 to get -97.

$$-\frac{97}{8}-\left(-5\right)^{2}$$

Calculate -5 to the power of 2 and get 25.

$$-\frac{97}{8}-25$$

Convert 25 to fraction \frac{200}{8}.

$$-\frac{97}{8}-\frac{200}{8}$$

Since -\frac{97}{8} and \frac{200}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-97-200}{8}$$

Subtract 200 from -97 to get -297.

$$-\frac{297}{8}$$

Factor

$$-37.125$$