Solve -1^0-2^-1*3^-1*[2-(-3)^2]

$$- 1 ^ { 0 } - 2 ^ { - 1 } \times 3 ^ { - 1 } \times [ 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$\frac{1}{6}\approx 0.166666667$$

Solution Steps

Calculate 1 to the power of 0 and get 1.

$$-1-2^{-1}\times 3^{-1}\left(2-\left(-3\right)^{2}\right)$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$-1-\frac{1}{2}\times 3^{-1}\left(2-\left(-3\right)^{2}\right)$$

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$-1-\frac{1}{2}\times \frac{1}{3}\left(2-\left(-3\right)^{2}\right)$$

Multiply \frac{1}{2} and \frac{1}{3} to get \frac{1}{6}.

$$-1-\frac{1}{6}\left(2-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$-1-\frac{1}{6}\left(2-9\right)$$

Subtract 9 from 2 to get -7.

$$-1-\frac{1}{6}\left(-7\right)$$

Multiply \frac{1}{6} and -7 to get -\frac{7}{6}.

$$-1-\left(-\frac{7}{6}\right)$$

The opposite of -\frac{7}{6} is \frac{7}{6}.

$$-1+\frac{7}{6}$$

Add -1 and \frac{7}{6} to get \frac{1}{6}.

$$\frac{1}{6}$$

Factor

$$\frac{1}{2 \cdot 3} = 0.16666666666666666$$