Solve -1=1/2x-2+b

$$- 1 = \frac { 1 } { 2 } x - 2 + b$$

Solve for b

$$b=-\frac{x}{2}+1$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}x-2+b=-1$$

Subtract \frac{1}{2}x from both sides.

$$-2+b=-1-\frac{1}{2}x$$

Add 2 to both sides.

$$b=-1-\frac{1}{2}x+2$$

Add -1 and 2 to get 1.

$$b=1-\frac{1}{2}x$$

Solve for x

$$x=2-2b$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}x-2+b=-1$$

Add 2 to both sides.

$$\frac{1}{2}x+b=-1+2$$

Add -1 and 2 to get 1.

$$\frac{1}{2}x+b=1$$

Subtract b from both sides.

$$\frac{1}{2}x=1-b$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{1-b}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$x=\frac{1-b}{\frac{1}{2}}$$

Divide 1-b by \frac{1}{2} by multiplying 1-b by the reciprocal of \frac{1}{2}.

$$x=2-2b$$