Solve -1+1/3x=-4/15y

$$- 1 + \frac { 1 } { 3 } x = - \frac { 4 } { 15 } y$$

Solve for x

$$x=-\frac{4y}{5}+3$$

Steps for Solving Linear Equation

Add 1 to both sides.

$$\frac{1}{3}x=-\frac{4}{15}y+1$$

The equation is in standard form.

$$\frac{1}{3}x=-\frac{4y}{15}+1$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{-\frac{4y}{15}+1}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{-\frac{4y}{15}+1}{\frac{1}{3}}$$

Divide -\frac{4y}{15}+1 by \frac{1}{3} by multiplying -\frac{4y}{15}+1 by the reciprocal of \frac{1}{3}.

$$x=-\frac{4y}{5}+3$$

Solve for y

$$y=\frac{15-5x}{4}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{4}{15}y=-1+\frac{1}{3}x$$

The equation is in standard form.

$$-\frac{4}{15}y=\frac{x}{3}-1$$

Divide both sides of the equation by -\frac{4}{15}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{4}{15}y}{-\frac{4}{15}}=\frac{\frac{x}{3}-1}{-\frac{4}{15}}$$

Dividing by -\frac{4}{15} undoes the multiplication by -\frac{4}{15}.

$$y=\frac{\frac{x}{3}-1}{-\frac{4}{15}}$$

Divide -1+\frac{x}{3} by -\frac{4}{15} by multiplying -1+\frac{x}{3} by the reciprocal of -\frac{4}{15}.

$$y=\frac{15-5x}{4}$$