Solve -0.6-16/3+91/3+(-11/5)

$$- 0.6 - \frac { 16 } { 3 } + 9 \frac { 1 } { 3 } + ( - 1 \frac { 1 } { 5 } )$$

Evaluate

$$2.2$$

Solution Steps

Convert decimal number -0.6 to fraction -\frac{6}{10}. Reduce the fraction -\frac{6}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{3}{5}-\frac{16}{3}+\frac{9\times 3+1}{3}-\frac{1\times 5+1}{5}$$

Least common multiple of 5 and 3 is 15. Convert -\frac{3}{5} and \frac{16}{3} to fractions with denominator 15.

$$-\frac{9}{15}-\frac{80}{15}+\frac{9\times 3+1}{3}-\frac{1\times 5+1}{5}$$

Since -\frac{9}{15} and \frac{80}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-9-80}{15}+\frac{9\times 3+1}{3}-\frac{1\times 5+1}{5}$$

Subtract 80 from -9 to get -89.

$$-\frac{89}{15}+\frac{9\times 3+1}{3}-\frac{1\times 5+1}{5}$$

Multiply 9 and 3 to get 27.

$$-\frac{89}{15}+\frac{27+1}{3}-\frac{1\times 5+1}{5}$$

Add 27 and 1 to get 28.

$$-\frac{89}{15}+\frac{28}{3}-\frac{1\times 5+1}{5}$$

Least common multiple of 15 and 3 is 15. Convert -\frac{89}{15} and \frac{28}{3} to fractions with denominator 15.

$$-\frac{89}{15}+\frac{140}{15}-\frac{1\times 5+1}{5}$$

Since -\frac{89}{15} and \frac{140}{15} have the same denominator, add them by adding their numerators.

$$\frac{-89+140}{15}-\frac{1\times 5+1}{5}$$

Add -89 and 140 to get 51.

$$\frac{51}{15}-\frac{1\times 5+1}{5}$$

Reduce the fraction \frac{51}{15} to lowest terms by extracting and canceling out 3.

$$\frac{17}{5}-\frac{1\times 5+1}{5}$$

Multiply 1 and 5 to get 5.

$$\frac{17}{5}-\frac{5+1}{5}$$

Add 5 and 1 to get 6.

$$\frac{17}{5}-\frac{6}{5}$$

Since \frac{17}{5} and \frac{6}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-6}{5}$$

Subtract 6 from 17 to get 11.

$$\frac{11}{5}$$

Factor

$$\frac{11}{5} = 2\frac{1}{5} = 2.2$$