Solve -0,1*(-2)^4+0,1*(-2)^3+1,2*(-2)^2+3

$$- 0,1 \cdot ( - 2 ) ^ { 4 } + 0,1 \cdot ( - 2 ) ^ { 3 } + 1,2 \cdot ( - 2 ) ^ { 2 } + 3$$

Evaluate

$$5,4$$

Solution Steps

Calculate -2 to the power of 4 and get 16.

$$-0,1\times 16+0,1\left(-2\right)^{3}+1,2\left(-2\right)^{2}+3$$

Multiply -0,1 and 16 to get -1,6.

$$-1,6+0,1\left(-2\right)^{3}+1,2\left(-2\right)^{2}+3$$

Calculate -2 to the power of 3 and get -8.

$$-1,6+0,1\left(-8\right)+1,2\left(-2\right)^{2}+3$$

Multiply 0,1 and -8 to get -0,8.

$$-1,6-0,8+1,2\left(-2\right)^{2}+3$$

Subtract 0,8 from -1,6 to get -2,4.

$$-2,4+1,2\left(-2\right)^{2}+3$$

Calculate -2 to the power of 2 and get 4.

$$-2,4+1,2\times 4+3$$

Multiply 1,2 and 4 to get 4,8.

$$-2,4+4,8+3$$

Add -2,4 and 4,8 to get 2,4.

$$2,4+3$$

Add 2,4 and 3 to get 5,4.

$$5,4$$

Factor

$$\frac{3 ^ {3}}{5} = 5\frac{2}{5} = 5.4$$