Solve -(x-1)(-x+3)=0

$$- ( x - 1 ) ( - x + 3 ) = 0$$

Solve for x

$$x=3$$

$$x=1$$

Steps Using Factoring

To find the opposite of x-1, find the opposite of each term.

$$\left(-x-\left(-1\right)\right)\left(-x+3\right)=0$$

The opposite of -1 is 1.

$$\left(-x+1\right)\left(-x+3\right)=0$$

Apply the distributive property by multiplying each term of -x+1 by each term of -x+3.

$$-x\left(-x\right)-3x-x+3=0$$

Multiply -1 and -1 to get 1.

$$xx-3x-x+3=0$$

Multiply x and x to get x^{2}.

$$x^{2}-3x-x+3=0$$

Combine -3x and -x to get -4x.

$$x^{2}-4x+3=0$$

To solve the equation, factor x^{2}-4x+3 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.

$$a+b=-4 ab=3$$

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. The only such pair is the system solution.

$$a=-3 b=-1$$

Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.

$$\left(x-3\right)\left(x-1\right)$$

To find equation solutions, solve x-3=0 and x-1=0.

$$x=3 x=1$$

Steps Using Factoring By Grouping

To find the opposite of x-1, find the opposite of each term.

$$\left(-x-\left(-1\right)\right)\left(-x+3\right)=0$$

The opposite of -1 is 1.

$$\left(-x+1\right)\left(-x+3\right)=0$$

Apply the distributive property by multiplying each term of -x+1 by each term of -x+3.

$$-x\left(-x\right)-3x-x+3=0$$

Multiply -1 and -1 to get 1.

$$xx-3x-x+3=0$$

Multiply x and x to get x^{2}.

$$x^{2}-3x-x+3=0$$

Combine -3x and -x to get -4x.

$$x^{2}-4x+3=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+3. To find a and b, set up a system to be solved.

$$a+b=-4 ab=1\times 3=3$$

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. The only such pair is the system solution.

$$a=-3 b=-1$$

Rewrite x^{2}-4x+3 as \left(x^{2}-3x\right)+\left(-x+3\right).

$$\left(x^{2}-3x\right)+\left(-x+3\right)$$

Factor out x in the first and -1 in the second group.

$$x\left(x-3\right)-\left(x-3\right)$$

Factor out common term x-3 by using distributive property.

$$\left(x-3\right)\left(x-1\right)$$

To find equation solutions, solve x-3=0 and x-1=0.

$$x=3 x=1$$

Steps Using the Quadratic Formula

To find the opposite of x-1, find the opposite of each term.

$$\left(-x-\left(-1\right)\right)\left(-x+3\right)=0$$

The opposite of -1 is 1.

$$\left(-x+1\right)\left(-x+3\right)=0$$

Apply the distributive property by multiplying each term of -x+1 by each term of -x+3.

$$-x\left(-x\right)-3x-x+3=0$$

Multiply -1 and -1 to get 1.

$$xx-3x-x+3=0$$

Multiply x and x to get x^{2}.

$$x^{2}-3x-x+3=0$$

Combine -3x and -x to get -4x.

$$x^{2}-4x+3=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -4 for b, and 3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 3}}{2}$$

Square -4.

$$x=\frac{-\left(-4\right)±\sqrt{16-4\times 3}}{2}$$

Multiply -4 times 3.

$$x=\frac{-\left(-4\right)±\sqrt{16-12}}{2}$$

Add 16 to -12.

$$x=\frac{-\left(-4\right)±\sqrt{4}}{2}$$

Take the square root of 4.

$$x=\frac{-\left(-4\right)±2}{2}$$

The opposite of -4 is 4.

$$x=\frac{4±2}{2}$$

Now solve the equation x=\frac{4±2}{2} when ± is plus. Add 4 to 2.

$$x=\frac{6}{2}$$

Divide 6 by 2.

$$x=3$$

Now solve the equation x=\frac{4±2}{2} when ± is minus. Subtract 2 from 4.

$$x=\frac{2}{2}$$

Divide 2 by 2.

$$x=1$$

The equation is now solved.

$$x=3 x=1$$

Steps for Completing the Square

To find the opposite of x-1, find the opposite of each term.

$$\left(-x-\left(-1\right)\right)\left(-x+3\right)=0$$

The opposite of -1 is 1.

$$\left(-x+1\right)\left(-x+3\right)=0$$

Apply the distributive property by multiplying each term of -x+1 by each term of -x+3.

$$-x\left(-x\right)-3x-x+3=0$$

Multiply -1 and -1 to get 1.

$$xx-3x-x+3=0$$

Multiply x and x to get x^{2}.

$$x^{2}-3x-x+3=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$x^{2}-3x-x=-3$$

Combine -3x and -x to get -4x.

$$x^{2}-4x=-3$$

Divide -4, the coefficient of the x term, by 2 to get -2. Then add the square of -2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-4x+\left(-2\right)^{2}=-3+\left(-2\right)^{2}$$

Square -2.

$$x^{2}-4x+4=-3+4$$

Add -3 to 4.

$$x^{2}-4x+4=1$$

Factor x^{2}-4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-2\right)^{2}=1$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-2\right)^{2}}=\sqrt{1}$$

Simplify.

$$x-2=1 x-2=-1$$

Add 2 to both sides of the equation.

$$x=3 x=1$$