Solve -(2x)^2+1=-3

$$- ( 2 x ) ^ { 2 } + 1 = - 3$$

Solve for x

$$x=1$$

$$x=-1$$

Steps by Finding Square Root

Expand \left(2x\right)^{2}.

$$-2^{2}x^{2}+1=-3$$

Calculate 2 to the power of 2 and get 4.

$$-4x^{2}+1=-3$$

Subtract 1 from both sides.

$$-4x^{2}=-3-1$$

Subtract 1 from -3 to get -4.

$$-4x^{2}=-4$$

Divide both sides by -1.

$$4x^{2}=\frac{-4}{-1}$$

Fraction \frac{-4}{-1} can be simplified to 4 by removing the negative sign from both the numerator and the denominator.

$$4x^{2}=4$$

Divide both sides by 4.

$$x^{2}=\frac{4}{4}$$

Divide 4 by 4 to get 1.

$$x^{2}=1$$

Take the square root of both sides of the equation.

$$x=1 x=-1$$