Solve for a
a=\frac{y-7}{2}
Solve for y
y=2a+7
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-2a+1=8-y
To find the opposite of 2a-1, find the opposite of each term.
-2a=8-y-1
Subtract 1 from both sides.
-2a=7-y
Subtract 1 from 8 to get 7.
\frac{-2a}{-2}=\frac{7-y}{-2}
Divide both sides by -2.
a=\frac{7-y}{-2}
Dividing by -2 undoes the multiplication by -2.
a=\frac{y-7}{2}
Divide 7-y by -2.
-2a+1=8-y
To find the opposite of 2a-1, find the opposite of each term.
8-y=-2a+1
Swap sides so that all variable terms are on the left hand side.
-y=-2a+1-8
Subtract 8 from both sides.
-y=-2a-7
Subtract 8 from 1 to get -7.
\frac{-y}{-1}=\frac{-2a-7}{-1}
Divide both sides by -1.
y=\frac{-2a-7}{-1}
Dividing by -1 undoes the multiplication by -1.
y=2a+7
Divide -2a-7 by -1.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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