Solve -(-8)^{3}-frac{5^{3}*(-7)^0}{12^0}-(-6)*7^2/9^0

$$- ( - 8 ) ^ { 3 } - \frac { 5 ^ { 3 } \cdot ( - 7 ) ^ { 0 } } { 12 ^ { 0 } } - ( - 6 ) \cdot \frac { 7 ^ { 2 } } { 9 ^ { 0 } }$$

Evaluate

$$681$$

Solution Steps

Calculate -8 to the power of 3 and get -512.

$$-\left(-512\right)-\frac{5^{3}\left(-7\right)^{0}}{12^{0}}-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

The opposite of -512 is 512.

$$512-\frac{5^{3}\left(-7\right)^{0}}{12^{0}}-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

Calculate 5 to the power of 3 and get 125.

$$512-\frac{125\left(-7\right)^{0}}{12^{0}}-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

Calculate -7 to the power of 0 and get 1.

$$512-\frac{125\times 1}{12^{0}}-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

Multiply 125 and 1 to get 125.

$$512-\frac{125}{12^{0}}-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

Calculate 12 to the power of 0 and get 1.

$$512-\frac{125}{1}-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

Anything divided by one gives itself.

$$512-125-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

Subtract 125 from 512 to get 387.

$$387-\left(-6\times \frac{7^{2}}{9^{0}}\right)$$

Calculate 7 to the power of 2 and get 49.

$$387-\left(-6\times \frac{49}{9^{0}}\right)$$

Calculate 9 to the power of 0 and get 1.

$$387-\left(-6\times \frac{49}{1}\right)$$

Anything divided by one gives itself.

$$387-\left(-6\times 49\right)$$

Multiply -6 and 49 to get -294.

$$387-\left(-294\right)$$

The opposite of -294 is 294.

$$387+294$$

Add 387 and 294 to get 681.

$$681$$

Factor

$$3\times 227$$