- ( - 8 + 12 q ) = - 4 ( - 2 q
Solve for q
q=\frac{2}{5}=0.4
Share
Copied to clipboard
-\left(-8\right)-12q=-4\left(-2\right)q
To find the opposite of -8+12q, find the opposite of each term.
8-12q=-4\left(-2\right)q
The opposite of -8 is 8.
8-12q=8q
Multiply -4 and -2 to get 8.
8-12q-8q=0
Subtract 8q from both sides.
8-20q=0
Combine -12q and -8q to get -20q.
-20q=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
q=\frac{-8}{-20}
Divide both sides by -20.
q=\frac{2}{5}
Reduce the fraction \frac{-8}{-20} to lowest terms by extracting and canceling out -4.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}