Solve -(-3+2)^3*7-(-5^2*4+sqrt{16})+5^2*4-(-48:12)^2=

$$- ( - 3 + 2 ) ^ { 3 } \cdot 7 - ( - 5 ^ { 2 } \cdot 4 + \sqrt { 16 } ) + 5 ^ { 2 } \cdot 4 - ( - 48 : 12 ) ^ { 2 } =$$

Evaluate

$$187$$

Solution Steps

Add -3 and 2 to get -1.

$$\left(-\left(-1\right)^{3}\right)\times 7-\left(\left(-5^{2}\right)\times 4+\sqrt{16}\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Calculate -1 to the power of 3 and get -1.

$$\left(-\left(-1\right)\right)\times 7-\left(\left(-5^{2}\right)\times 4+\sqrt{16}\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

The opposite of -1 is 1.

$$1\times 7-\left(\left(-5^{2}\right)\times 4+\sqrt{16}\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Multiply 1 and 7 to get 7.

$$7-\left(\left(-5^{2}\right)\times 4+\sqrt{16}\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Calculate 5 to the power of 2 and get 25.

$$7-\left(-25\times 4+\sqrt{16}\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Multiply -25 and 4 to get -100.

$$7-\left(-100+\sqrt{16}\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Calculate the square root of 16 and get 4.

$$7-\left(-100+4\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Add -100 and 4 to get -96.

$$7-\left(-96\right)+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

The opposite of -96 is 96.

$$7+96+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Add 7 and 96 to get 103.

$$103+5^{2}\times 4-\left(\frac{-48}{12}\right)^{2}$$

Calculate 5 to the power of 2 and get 25.

$$103+25\times 4-\left(\frac{-48}{12}\right)^{2}$$

Multiply 25 and 4 to get 100.

$$103+100-\left(\frac{-48}{12}\right)^{2}$$

Add 103 and 100 to get 203.

$$203-\left(\frac{-48}{12}\right)^{2}$$

Divide -48 by 12 to get -4.

$$203-\left(-4\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$203-16$$

Subtract 16 from 203 to get 187.

$$187$$

Factor

$$11\times 17$$