Solve -(-2)^{3}*(-2)^{2}+sqrt[3]{1-1}+5^{2}*0^9(-2)^3+(1^3)^2=

$$- ( - 2 ) ^ { 3 } \cdot ( - 2 ) ^ { 2 } + \sqrt[ 3 ] { 1 - 1 } + 5 ^ { 2 } \cdot 0 ^ { 9 } ( - 2 ) ^ { 3 } + ( 1 ^ { 3 } ) ^ { 2 } =$$

Evaluate

$$33$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$\left(-\left(-2\right)^{3}\right)\left(-2\right)^{2}+\sqrt[3]{1-1}+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Calculate -2 to the power of 3 and get -8.

$$\left(-\left(-8\right)\right)\left(-2\right)^{2}+\sqrt[3]{1-1}+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

The opposite of -8 is 8.

$$8\left(-2\right)^{2}+\sqrt[3]{1-1}+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Calculate -2 to the power of 2 and get 4.

$$8\times 4+\sqrt[3]{1-1}+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Multiply 8 and 4 to get 32.

$$32+\sqrt[3]{1-1}+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Subtract 1 from 1 to get 0.

$$32+\sqrt[3]{0}+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Calculate \sqrt[3]{0} and get 0.

$$32+0+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Add 32 and 0 to get 32.

$$32+5^{2}\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Calculate 5 to the power of 2 and get 25.

$$32+25\times 0^{9}\left(-2\right)^{3}+1^{6}$$

Calculate 0 to the power of 9 and get 0.

$$32+25\times 0\left(-2\right)^{3}+1^{6}$$

Multiply 25 and 0 to get 0.

$$32+0\left(-2\right)^{3}+1^{6}$$

Calculate -2 to the power of 3 and get -8.

$$32+0\left(-8\right)+1^{6}$$

Multiply 0 and -8 to get 0.

$$32+0+1^{6}$$

Add 32 and 0 to get 32.

$$32+1^{6}$$

Calculate 1 to the power of 6 and get 1.

$$32+1$$

Add 32 and 1 to get 33.

$$33$$

Factor

$$3\times 11$$