Solve -(-2)^3+(-1)^0-sqrt25-3^2-5^3:25

$$- ( - 2 ) ^ { 3 } + ( - 1 ) ^ { 0 } - \sqrt { 25 - 3 } ^ { 2 } - 5 ^ { 3 } : 25$$

Evaluate

$$-18$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-\left(-8\right)+\left(-1\right)^{0}-\left(\sqrt{25-3}\right)^{2}-\frac{5^{3}}{25}$$

The opposite of -8 is 8.

$$8+\left(-1\right)^{0}-\left(\sqrt{25-3}\right)^{2}-\frac{5^{3}}{25}$$

Calculate -1 to the power of 0 and get 1.

$$8+1-\left(\sqrt{25-3}\right)^{2}-\frac{5^{3}}{25}$$

Add 8 and 1 to get 9.

$$9-\left(\sqrt{25-3}\right)^{2}-\frac{5^{3}}{25}$$

Subtract 3 from 25 to get 22.

$$9-\left(\sqrt{22}\right)^{2}-\frac{5^{3}}{25}$$

The square of \sqrt{22} is 22.

$$9-22-\frac{5^{3}}{25}$$

Subtract 22 from 9 to get -13.

$$-13-\frac{5^{3}}{25}$$

Calculate 5 to the power of 3 and get 125.

$$-13-\frac{125}{25}$$

Divide 125 by 25 to get 5.

$$-13-5$$

Subtract 5 from -13 to get -18.

$$-18$$

Factor

$$-18$$