Solve -(-2)^3+(-1)^0-sqrt{25-3^2}-5

$$- ( - 2 ) ^ { 3 } + ( - 1 ) ^ { 0 } - \sqrt { 25 - 3 ^ { 2 } } - 5$$

Evaluate

$$0$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$-\left(-8\right)+\left(-1\right)^{0}-\sqrt{25-3^{2}}-5$$

The opposite of -8 is 8.

$$8+\left(-1\right)^{0}-\sqrt{25-3^{2}}-5$$

Calculate -1 to the power of 0 and get 1.

$$8+1-\sqrt{25-3^{2}}-5$$

Add 8 and 1 to get 9.

$$9-\sqrt{25-3^{2}}-5$$

Calculate 3 to the power of 2 and get 9.

$$9-\sqrt{25-9}-5$$

Subtract 9 from 25 to get 16.

$$9-\sqrt{16}-5$$

Calculate the square root of 16 and get 4.

$$9-4-5$$

Subtract 4 from 9 to get 5.

$$5-5$$

Subtract 5 from 5 to get 0.

$$0$$

Factor

$$0$$