Solve -(-1/2)^4div(-1/2)^6]*(-1/2)^6+2^-7=

$$- ( - \frac { 1 } { 2 } ) ^ { 4 } \div ( - \frac { 1 } { 2 } ) ^ { 6 } ] \cdot ( - \frac { 1 } { 2 } ) ^ { 6 } + 2 ^ { - 7 } =$$

Evaluate

$$-4$$

Solution Steps

Calculate -\frac{1}{2} to the power of 4 and get \frac{1}{16}.

$$\frac{-\frac{1}{16}}{\left(-\frac{1}{2}\right)^{6}}$$

Calculate -\frac{1}{2} to the power of 6 and get \frac{1}{64}.

$$\frac{-\frac{1}{16}}{\frac{1}{64}}$$

Divide -\frac{1}{16} by \frac{1}{64} by multiplying -\frac{1}{16} by the reciprocal of \frac{1}{64}.

$$-\frac{1}{16}\times 64$$

Express -\frac{1}{16}\times 64 as a single fraction.

$$\frac{-64}{16}$$

Divide -64 by 16 to get -4.

$$-4$$

Factor

$$-4$$