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-\left(\left(\sqrt{3}\right)^{2}-2\sqrt{3}+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-1\right)^{2}.
-\left(3-2\sqrt{3}+1\right)
The square of \sqrt{3} is 3.
-\left(4-2\sqrt{3}\right)
Add 3 and 1 to get 4.
-4+2\sqrt{3}
To find the opposite of 4-2\sqrt{3}, find the opposite of each term.
-\left(\left(\sqrt{3}\right)^{2}-2\sqrt{3}+1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{3}-1\right)^{2}.
-\left(3-2\sqrt{3}+1\right)
The square of \sqrt{3} is 3.
-\left(4-2\sqrt{3}\right)
Add 3 and 1 to get 4.
-4+2\sqrt{3}
To find the opposite of 4-2\sqrt{3}, find the opposite of each term.