Solve -(5/9+20/81+40/729)=

$$- ( \frac { 5 } { 9 } + \frac { 20 } { 81 } + \frac { 40 } { 729 } ) =$$

Evaluate

$$-\frac{625}{729}\approx -0.85733882$$

Solution Steps

Least common multiple of 9 and 81 is 81. Convert \frac{5}{9} and \frac{20}{81} to fractions with denominator 81.

$$-\left(\frac{45}{81}+\frac{20}{81}+\frac{40}{729}\right)$$

Since \frac{45}{81} and \frac{20}{81} have the same denominator, add them by adding their numerators.

$$-\left(\frac{45+20}{81}+\frac{40}{729}\right)$$

Add 45 and 20 to get 65.

$$-\left(\frac{65}{81}+\frac{40}{729}\right)$$

Least common multiple of 81 and 729 is 729. Convert \frac{65}{81} and \frac{40}{729} to fractions with denominator 729.

$$-\left(\frac{585}{729}+\frac{40}{729}\right)$$

Since \frac{585}{729} and \frac{40}{729} have the same denominator, add them by adding their numerators.

$$-\frac{585+40}{729}$$

Add 585 and 40 to get 625.

$$-\frac{625}{729}$$

Factor

$$-\frac{625}{729} = -0.8573388203017832$$