Solve -(1/3)^4:(-1/3)^2=

$$- ( \frac { 1 } { 3 } ) ^ { 4 } : ( - \frac { 1 } { 3 } ) ^ { 2 } =$$

Evaluate

$$-\frac{1}{9}\approx -0.111111111$$

Solution Steps

Calculate \frac{1}{3} to the power of 4 and get \frac{1}{81}.

$$\frac{-\frac{1}{81}}{\left(-\frac{1}{3}\right)^{2}}$$

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{-\frac{1}{81}}{\frac{1}{9}}$$

Divide -\frac{1}{81} by \frac{1}{9} by multiplying -\frac{1}{81} by the reciprocal of \frac{1}{9}.

$$-\frac{1}{81}\times 9$$

Express -\frac{1}{81}\times 9 as a single fraction.

$$\frac{-9}{81}$$

Reduce the fraction \frac{-9}{81} to lowest terms by extracting and canceling out 9.

$$-\frac{1}{9}$$

Factor

$$-\frac{1}{9} = -0.1111111111111111$$