Solve -(+31/2)+(-11/6)=

$$- ( + 3 \frac { 1 } { 2 } ) + ( - 1 \frac { 1 } { 6 } ) =$$

Evaluate

$$-\frac{14}{3}\approx -4.666666667$$

Solution Steps

Multiply 3 and 2 to get 6.

$$-\frac{6+1}{2}-\frac{1\times 6+1}{6}$$

Add 6 and 1 to get 7.

$$-\frac{7}{2}-\frac{1\times 6+1}{6}$$

Multiply 1 and 6 to get 6.

$$-\frac{7}{2}-\frac{6+1}{6}$$

Add 6 and 1 to get 7.

$$-\frac{7}{2}-\frac{7}{6}$$

Least common multiple of 2 and 6 is 6. Convert -\frac{7}{2} and \frac{7}{6} to fractions with denominator 6.

$$-\frac{21}{6}-\frac{7}{6}$$

Since -\frac{21}{6} and \frac{7}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-21-7}{6}$$

Subtract 7 from -21 to get -28.

$$\frac{-28}{6}$$

Reduce the fraction \frac{-28}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{14}{3}$$

Factor

$$-\frac{14}{3} = -4\frac{2}{3} = -4.666666666666667$$