Solve -|-18|div(-11/5)-6div(-2)*(-1/3)

$$- | - 18 | \div ( - 1 \frac { 1 } { 5 } ) - 6 \div ( - 2 ) \times ( - \frac { 1 } { 3 } )$$

Evaluate

$$14$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -18 is 18.

$$\frac{-18}{-\frac{1\times 5+1}{5}}-\frac{6}{-2}\left(-\frac{1}{3}\right)$$

Multiply 1 and 5 to get 5.

$$\frac{-18}{-\frac{5+1}{5}}-\frac{6}{-2}\left(-\frac{1}{3}\right)$$

Add 5 and 1 to get 6.

$$\frac{-18}{-\frac{6}{5}}-\frac{6}{-2}\left(-\frac{1}{3}\right)$$

Divide -18 by -\frac{6}{5} by multiplying -18 by the reciprocal of -\frac{6}{5}.

$$-18\left(-\frac{5}{6}\right)-\frac{6}{-2}\left(-\frac{1}{3}\right)$$

Express -18\left(-\frac{5}{6}\right) as a single fraction.

$$\frac{-18\left(-5\right)}{6}-\frac{6}{-2}\left(-\frac{1}{3}\right)$$

Multiply -18 and -5 to get 90.

$$\frac{90}{6}-\frac{6}{-2}\left(-\frac{1}{3}\right)$$

Divide 90 by 6 to get 15.

$$15-\frac{6}{-2}\left(-\frac{1}{3}\right)$$

Divide 6 by -2 to get -3.

$$15-\left(-3\left(-\frac{1}{3}\right)\right)$$

Multiply -3 times -\frac{1}{3}.

$$15-1$$

Subtract 1 from 15 to get 14.

$$14$$

Factor

$$2\times 7$$