Solve -4^3+4*-4^2-7*-4-10>0

$$- { 4 }^{ 3 } +4 \times - { 4 }^{ 2 } -7 \times -4-10 > 0$$

Verify

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$-64+4\left(-4^{2}\right)-7\left(-4\right)-10>0$$

Calculate 4 to the power of 2 and get 16.

$$-64+4\left(-16\right)-7\left(-4\right)-10>0$$

Multiply 4 and -16 to get -64.

$$-64-64-7\left(-4\right)-10>0$$

Subtract 64 from -64 to get -128.

$$-128-7\left(-4\right)-10>0$$

Multiply 7 and -4 to get -28.

$$-128-\left(-28\right)-10>0$$

The opposite of -28 is 28.

$$-128+28-10>0$$

Add -128 and 28 to get -100.

$$-100-10>0$$

Subtract 10 from -100 to get -110.

$$-110>0$$

Compare -110 and 0.

$$\text{false}$$