Solve -4^3+2*-4^2-9*-4-18

$$- { 4 }^{ 3 } +2 \times - { 4 }^{ 2 } -9 \times -4-18$$

Evaluate

$$-78$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$-64+2\left(-4^{2}\right)-9\left(-4\right)-18$$

Calculate 4 to the power of 2 and get 16.

$$-64+2\left(-16\right)-9\left(-4\right)-18$$

Multiply 2 and -16 to get -32.

$$-64-32-9\left(-4\right)-18$$

Subtract 32 from -64 to get -96.

$$-96-9\left(-4\right)-18$$

Multiply 9 and -4 to get -36.

$$-96-\left(-36\right)-18$$

The opposite of -36 is 36.

$$-96+36-18$$

Add -96 and 36 to get -60.

$$-60-18$$

Subtract 18 from -60 to get -78.

$$-78$$

Factor

$$-78$$