Solve -3^2-4left(-3+2right)--1/-3+-3

$$- { 3 }^{ 2 } - \frac{ 4 \left( -3+2 \right) --1 }{ -3+-3 }$$

Evaluate

$$-\frac{19}{2}=-9.5$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$-9-\frac{4\left(-3+2\right)-\left(-1\right)}{-3-3}$$

Add -3 and 2 to get -1.

$$-9-\frac{4\left(-1\right)-\left(-1\right)}{-3-3}$$

Multiply 4 and -1 to get -4.

$$-9-\frac{-4-\left(-1\right)}{-3-3}$$

The opposite of -1 is 1.

$$-9-\frac{-4+1}{-3-3}$$

Add -4 and 1 to get -3.

$$-9-\frac{-3}{-3-3}$$

Subtract 3 from -3 to get -6.

$$-9-\frac{-3}{-6}$$

Reduce the fraction \frac{-3}{-6} to lowest terms by extracting and canceling out -3.

$$-9-\frac{1}{2}$$

Convert -9 to fraction -\frac{18}{2}.

$$-\frac{18}{2}-\frac{1}{2}$$

Since -\frac{18}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-18-1}{2}$$

Subtract 1 from -18 to get -19.

$$-\frac{19}{2}$$

Factor

$$-\frac{19}{2} = -9\frac{1}{2} = -9.5$$