Solve -2^3div(-1/6)-1/4*-2^2

$$- { 2 }^{ 3 } \div (- \frac{ 1 }{ 6 } )- \frac{ 1 }{ 4 } \times - { 2 }^{ 2 }$$

Evaluate

$$49$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{-8}{-\frac{1}{6}}-\frac{1}{4}\left(-2^{2}\right)$$

Divide -8 by -\frac{1}{6} by multiplying -8 by the reciprocal of -\frac{1}{6}.

$$-8\left(-6\right)-\frac{1}{4}\left(-2^{2}\right)$$

Multiply -8 and -6 to get 48.

$$48-\frac{1}{4}\left(-2^{2}\right)$$

Calculate 2 to the power of 2 and get 4.

$$48-\frac{1}{4}\left(-4\right)$$

Multiply \frac{1}{4} and -4 to get \frac{-4}{4}.

$$48-\frac{-4}{4}$$

Divide -4 by 4 to get -1.

$$48-\left(-1\right)$$

The opposite of -1 is 1.

$$48+1$$

Add 48 and 1 to get 49.

$$49$$

Factor

$$7^{2}$$