Solve -2^2-2-2-3*8^2-2*8-3

$$- { 2 }^{ 2 } -2-2-3 \times { 8 }^{ 2 } -2 \cdot 8-3$$

Evaluate

$$-219$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$-4-2-2-3\times 8^{2}-2\times 8-3$$

Subtract 2 from -4 to get -6.

$$-6-2-3\times 8^{2}-2\times 8-3$$

Subtract 2 from -6 to get -8.

$$-8-3\times 8^{2}-2\times 8-3$$

Calculate 8 to the power of 2 and get 64.

$$-8-3\times 64-2\times 8-3$$

Multiply 3 and 64 to get 192.

$$-8-192-2\times 8-3$$

Subtract 192 from -8 to get -200.

$$-200-2\times 8-3$$

Multiply 2 and 8 to get 16.

$$-200-16-3$$

Subtract 16 from -200 to get -216.

$$-216-3$$

Subtract 3 from -216 to get -219.

$$-219$$

Factor

$$-219$$