Solve -1^2-2*1+x

$$- { 1 }^{ 2 } -2 \times 1+x$$

Evaluate

$$x-3$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$-1-2\times 1+x$$

Multiply 2 and 1 to get 2.

$$-1-2+x$$

Subtract 2 from -1 to get -3.

$$-3+x$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

Calculate 1 to the power of 2 and get 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-1-2\times 1+x)$$

Multiply 2 and 1 to get 2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-1-2+x)$$

Subtract 2 from -1 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3+x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$