Solve -1^2-{left(1/2right)}^3div4

$$- { 1 }^{ 2 } - { \left( \frac{ 1 }{ 2 } \right) }^{ 3 } \div 4$$

Evaluate

$$-\frac{33}{32}=-1.03125$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$-1-\frac{\left(\frac{1}{2}\right)^{3}}{4}$$

Calculate \frac{1}{2} to the power of 3 and get \frac{1}{8}.

$$-1-\frac{\frac{1}{8}}{4}$$

Express \frac{\frac{1}{8}}{4} as a single fraction.

$$-1-\frac{1}{8\times 4}$$

Multiply 8 and 4 to get 32.

$$-1-\frac{1}{32}$$

Convert -1 to fraction -\frac{32}{32}.

$$-\frac{32}{32}-\frac{1}{32}$$

Since -\frac{32}{32} and \frac{1}{32} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-32-1}{32}$$

Subtract 1 from -32 to get -33.

$$-\frac{33}{32}$$

Factor

$$-\frac{33}{32} = -1\frac{1}{32} = -1.03125$$