Solve -left(0-1+mright)^2+2=-1

$$- { \left(0-1+m \right) }^{ 2 } +2 = -1$$

Solve for m

$$m=\sqrt{3}+1\approx 2.732050808$$

$$m=1-\sqrt{3}\approx -0.732050808$$

Steps by Finding Square Root

Subtract 2 from both sides of the equation.

$$-\left(m-1\right)^{2}+2-2=-1-2$$

Subtracting 2 from itself leaves 0.

$$-\left(m-1\right)^{2}=-1-2$$

Subtract 2 from -1.

$$-\left(m-1\right)^{2}=-3$$

Divide both sides by -1.

$$\frac{-\left(m-1\right)^{2}}{-1}=-\frac{3}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$\left(m-1\right)^{2}=-\frac{3}{-1}$$

Divide -3 by -1.

$$\left(m-1\right)^{2}=3$$

Take the square root of both sides of the equation.

$$m-1=\sqrt{3} m-1=-\sqrt{3}$$

Add 1 to both sides of the equation.

$$m-1-\left(-1\right)=\sqrt{3}-\left(-1\right) m-1-\left(-1\right)=-\sqrt{3}-\left(-1\right)$$

Subtracting -1 from itself leaves 0.

$$m=\sqrt{3}-\left(-1\right) m=-\sqrt{3}-\left(-1\right)$$

Subtract -1 from \sqrt{3}.

$$m=\sqrt{3}+1$$

Subtract -1 from -\sqrt{3}.

$$m=1-\sqrt{3}$$

The equation is now solved.

$$m=\sqrt{3}+1 m=1-\sqrt{3}$$