Solve -{left(3/8right)}^2-3/8x+x/4=0

$$- { \left( \frac{ 3 }{ 8 } \right) }^{ 2 } - \frac{ 3 }{ 8 } x+ \frac{ x }{ 4 } =0$$

Solve for x

$$x = -\frac{9}{8} = -1\frac{1}{8} = -1.125$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8, the least common multiple of 8,4.

$$-8\times \left(\frac{3}{8}\right)^{2}-3x+2x=0$$

Calculate \frac{3}{8} to the power of 2 and get \frac{9}{64}.

$$-8\times \frac{9}{64}-3x+2x=0$$

Express -8\times \frac{9}{64} as a single fraction.

$$\frac{-8\times 9}{64}-3x+2x=0$$

Multiply -8 and 9 to get -72.

$$\frac{-72}{64}-3x+2x=0$$

Reduce the fraction \frac{-72}{64} to lowest terms by extracting and canceling out 8.

$$-\frac{9}{8}-3x+2x=0$$

Combine -3x and 2x to get -x.

$$-\frac{9}{8}-x=0$$

Add \frac{9}{8} to both sides. Anything plus zero gives itself.

$$-x=\frac{9}{8}$$

Multiply both sides by -1.

$$x=-\frac{9}{8}$$