Solve -sqrt{3}*sqrt{12}+sqrt{3}

$$- \sqrt{ 3 } \times \sqrt{ 12 } + \sqrt{ 3 }$$

Evaluate

$$\sqrt{3}-6\approx -4.267949192$$

Solution Steps

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$\left(-\sqrt{3}\right)\times 2\sqrt{3}+\sqrt{3}$$

Multiply -1 and 2 to get -2.

$$-2\sqrt{3}\sqrt{3}+\sqrt{3}$$

Multiply \sqrt{3} and \sqrt{3} to get 3.

$$-2\times 3+\sqrt{3}$$

Multiply -2 and 3 to get -6.

$$-6+\sqrt{3}$$

Factor

$$\sqrt{3} - 6 = -4.267949192$$